Not Enough Brownfield in the UK - Special Report
Gordon Brown's Government has promised three million new homes, 60% of them on brownfield land. But according to a report from the respected think
tank, Social Market Foundation (SMF), there's just not enough brownfield to go around. SMF has done its sums, and reckons that at normal housing densities, only enough brownfield land exists for one million new homes. In a report titled "Should The Green Belt Be Preserved?" (published 15th August 2007), it presents its thoughts:
There are three types of land on which new housing development can take place, previously developed land (PDL, or brownfield), greenfield, and green belt. The government has targeted PDL and by incentivisation through land remediation tax relief, and obstruction by planning barriers on greenfield and green belt land, it has achieved a situation where almost three quarters of recent new build has been on brownfield. But, the report points out, not all land categorised as PDL has previously been built on. It also includes areas like gardens and open spaces in towns and cities. Forcing more housing onto PDL deprives existing residents of gardens and parks.
The concentration on PDL cannot continue. According to SMF, "…even if all PDL (including gardens and city parks) were built on, the UK would fall short of its 3 million target for new housing. On Current Density trends, PDL could only accommodate 1 million new homes." To hit the government's target of 60% of homes built on PDL would require the housing density to be raised from the current minimum of 30 dwellings per hectare to 80 dwellings per hectare. That level is comparable with Current Density levels in London, and SMF believes that development at that level would seriously undermine quality of life for both old and new residents. Difficult decisions therefore need to be faced regarding development on greenfield and green belt land.
SMF looks at what is meant by green belt land. Contrary to popular opinion, it is not all green. Some of it is scrub land, and some is ex-industrial. It is not land of with exceptional landscape value, nor of scientific interest, nor a wildlife haven. Its defining characteristic is simply that it circles major towns and cities.
Greenfield land is, effectively, all land that is not PDL or green belt. 31% of it is classified as Areas of Outstanding Natural Beauty, National Parks, Sites of Special Scientific Interest or similar. It includes undeveloped land that would not widely be considered as outstandingly beautiful, as well as land that used to have development on it, but of which little now remains.
Given that the majority of the UK population would prefer to live in low density communities, and given the common misunderstandings about the nature and beauty of both green belt and greenfield land, SMF thinks that it is time for a debate about loosening the green belt if those three million new homes are to be ones that people actually enjoy living in.
The green belt surrounds existing cities. It contains towns and cities rather than protecting countryside - much of it is far less picturesque than popular belief. It is close to existing infrastructure and established communities. Because of its location it is likely that green belt land would have the highest levels of demand.
SMF suggests the options are:
* Deregulating green belt land that is not of any significant natural value and is well placed for housing, while offsetting that with increased protection for environmentally valuable land.
* Easing planning restrictions on the green belt, thereby allowing the market to determine where development takes place.
* Infill development in existing villages to increase their housing density and help protect environmentally valuable land.
The SMF concludes "The UK needs to have a rational debate about where to build these houses. We have to build them somewhere, but building new houses anywhere involves trade offs and winners and losers. The current debate, though, is scarred by misunderstandings. More than one half of Britons believe that 50% of land is developed, when the true figure is 13%. Most people believe the Green Belt is to protect wildlife or areas of beauty, when it is actually there to prevent urban sprawl."
The report's last lines are "The key is to design a planning system that empowers local people to shape their communities, while ensuring that everyone is able to put a roof over their heads. The UK has not managed to do this over recent decades. It is essential we get it right for the coming decades."
Scala Land Group (http://www.scalalandgroup.co.uk)
Article Source: ArticlesBase.com
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PHYSICS HELP!!!!? I need this answer in two days pls!!!!!!!!!!!!!!?
2.5m length of metal wire has a cross sectional area of 3.4*10^-6m^2 carries a current of 63 mA whenthe potential difference between it's ends is 13mV. Assuming the electric field is uniform within the wire, what is the magnitude? What is the current density in the wire? What is the resistivity of the metal?
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The resistivity of Aluminium is 2.8 × 10-8 m. How long a piece of Aluminium?
The resistivity of Aluminium is 2.8 × 10-8 m. How long a piece of Aluminium
wire 1 mm in diameter is needed to provide a resistance of 1.5?
(Answer to part 1)
l = ((1.5)(7.86 × 10-7) /( 2.8 × 10-8)) = 42.1 m
(its the next bit im stuck on!)
If the diameter of the wire in last Question was reduced to 0.2mm, but the length
kept constant calculate the new value of current density for an applied voltage of
3V.
(a) 37.5A
(b) 2.55 × 106 Am^-2
(c) 2.55 Am^-2
(d) 37.5 × 106 Am^-2
(e) none of the other answers are correct
Where do i start on this one? I don't understand most of the naming letters either.
listing A for area etc and r for radius
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density electron's drift speed?
A current of 0.131 mA flows in a silver wire whose cross-sectional area is 0.920 mm2. (The resistivity of silver is 1.62 10-8 ? m, and the density of silver is 10.49 g/cm3.)
(a) Find the density of electrons in the wire, assuming that there is one conduction electron per silver atom.
(b) Find the current density in the wire assuming that the current is uniform.
(c) Find the electron's drift speed.
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What is the drift speed of the electrons carrying this current?
What is the current density in an aluminum wire having a radius of 9 mm and carrying a current of 7 mA?
i got this J = I/A
and got 27.51 A/m^2
What is the drift speed of the electrons carrying this current? The density of aluminum is 2700 kg/m3, and 1 mole of aluminum has a mass of 26.98 g. There is one conduction electron per atom in aluminum.
this one i'm having trouble
thakn you
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If the diameter of the wire in last Question was reduced to 0.2mm, but the length?
The resistivity of Aluminium is 2.8 × 10^-8 m. How long a piece of Aluminium
wire 1 mm in diameter is needed to provide a resistance of 1.5?
(Answer to part 1)
l = ((1.5)(7.86 × 10-7) /( 2.8 × 10-8)) = 42.07 m
(its the next bit im stuck on!)
If the diameter of the wire in last Question was reduced to 0.2mm, but the length
kept constant calculate the new value of current density for an applied voltage of
3V.
(a) 37.5A
(b) 2.55 × 106 Am^-2
(c) 2.55 Am^-2
(d) 37.5 × 106 Am^-2
(e) none of the other answers are correct
Ok my calculations are probably wrong somewhere..
resistivity Al 28.2e-9 ?-m
R = ?L/A
? is resistivity of the material in ?-m
L is length in meters
A is cross-sectional area in m²
A = ?r², r is radius of wire in m
First calculate the new resistance of the wire with the new diameter
Area = Pi x (0.1x10^-3)
Area = 3.142x10^-8
So now using formula to calculate the resistance of the wire.
R= pL/A
R= (2.8x10^-8)(42.07)/(3.142x10^-8)
R= 37.5 Ohms
Next calculate the current using ohms law and the voltage
V/I*R
3/37.5 = 0.08 Amps
So i got the correct amps...
Next calculate the current density in amps per sq. meter by dividing that current by the cross-sectional area in meters²
Formula: I/A
So i did... 0.08/00000.3142 = 0.255Am^-2
The answer is apparently 2.55x10^6
(B)
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If the universe expanded from an infinitely dense point, how is its current density finite?
Even an enormous amount of expansion would not stop the density from being infinite.
I don't know how you would deal with an infinite amount of expansion of an infinitely dense area, any mathematicians?
Thanks a lot.
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if the current density of ordinary matter in the universe were 10 times as great as it is now we would expect?
more deuterium?
less deuterium?
about the same as current?
no deuterium?
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